88.8=16t^2

Solution for 88.8=16t^2 equation:

88.8=16t^2

We move all terms to the left:

88.8-(16t^2)=0

a = -16; b = 0; c = +88.8;
Δ = b2-4ac
Δ = 02-4·(-16)·88.8
Δ = 5683.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5683.2}}{2*-16}=\frac{0-\sqrt{5683.2}}{-32}
=-\frac{\sqrt{}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5683.2}}{2*-16}=\frac{0+\sqrt{5683.2}}{-32}
=\frac{\sqrt{}}{-32}
$